confusion in converting LBA to CHS

[brainbarshan]

I am reading the tutorial 6 bootloader 4 chapter
As written here :

absolute sector = (logical sector / sectors per track) + 1

and the code written after this:

xor dx, dx ; prepare dx:ax for operation
div WORD [bpbSectorsPerTrack] ; divide by sectors per track
inc dl ; add 1 (obsolute sector formula)
mov BYTE [absoluteSector], dl

But in 16 bit division , where AX stores the quotient and DX stores the remainder. Hence a remainder is being stored in dl and that is next stored in the variable absoluteSector.

Then the formula for calculating sector should have been :
absolute sector = (logical sector MOD sectors per track) + 1

correct me if I am wrong.

[Andyhhp]

You are correct. The calculation should use modulus.

~Andrew